Is this correct?
Find the equation of the tangent line to the curve y = 2x^3 - 5x -6 at x=2

f'(x) = 6x^2 - 5
m = f'(2) = 6(2)^2 - 5 = 19
point: (2, f(2)) = (2,0)
f(2) = 2(2)^3 - 5(2) - 6 = 0
y-y1 = m(x-x1)
y-(0) = 19(x-2)
y = 19x-2

Question

Is this correct?
Find the equation of the tangent line to the curve y = 2x^3 - 5x -6 at x=2

f'(x) = 6x^2 - 5
m = f'(2) = 6(2)^2 - 5 = 19
point: (2, f(2)) = (2,0)
f(2) = 2(2)^3 - 5(2) - 6 = 0
y-y1 = m(x-x1)
y-(0) = 19(x-2)
y = 19x-2

jim_thompson5910 · Answer

you forgot to distribute the 19 completely through

jim_thompson5910 · Answer

19(x-2) is NOT equivalent to 19x-2

anonymous · Answer

oh crap yea 19x - 38

jim_thompson5910 · Answer

good, everything else is perfect