Question

3X^3-81

Answer 1

if you want to factorise then take 3 as a common factor

\[3(x^3 - 27)\]

now you have the difference of 2 cubes

\[(a^3 - b^3) =(a - b)(a^2 + ab + b^2)\]

Answer 2

So how would it look in the difference of cubes formula

Answer 3

you need to find what the a and b represent and substitute them.

you also need to show the common factor of 3 outside the factorisation.

Answer 4

Does k stand for vertex

Answer 5

So how would it look in the difference of cubes formula

Answer 6

well x^3 so a = x

and 27 = 3^3 so b = 3