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Mathematics 19 Online
OpenStudy (anonymous):

what is csc^2x + csc^2x?

OpenStudy (anonymous):

in terms of what?

OpenStudy (anonymous):

Here's the whole problem: Prove that each equation is an identity. CSC^2x-COS^2x CSC^2X=1

OpenStudy (anonymous):

You have the left hand side =CSC^2x-COS^2xCSC^2X =cosec^2(x)-cos^2(x)cosec^2(x) =cosec^2(x)[1-cos^2(x)] =cosec^2(x)sin^2(x) =cosec^2(x)[1/cosec^2(x)] =cosec^2(x)/cosec^2(x) =1 =right hand side hence proved the identity.

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