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Mathematics 6 Online
OpenStudy (anonymous):

x^2 – rx + 1 = 0 has real roots and distinct root, then r does not lie between (A) 1 and 2 (B) – 1 and 1 (C) – 2 and 2 (D) – 1 and 2

OpenStudy (perl):

if the quadratic equation ax^2+bx+ c = 0 has two distinct real roots then the discriminant is positive. so b^2 - 4ac > 0 (-r)^2 -4 >0 r^2 > 4 r > 2 or r < -2

OpenStudy (perl):

so c) then r does not lie between 2 and -2 ,

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