Question

verify solution for : log(57x)= 2 + log (x-2)

Answer 1

i get x= 200/43 i am not sure if that is correct

Answer 2

how did you get that ?

Answer 3

\[\log(57x)= 2 + \log (x-2) \]
\[\log(57x)-\log(x-2)=\log (\frac{57x}{x-2})\]
\[\log (\frac{57x}{x-2})=2\]
\[10^2=\frac{57x}{x-2}\]
\[100x-200=57x\]
\[43x=200\]
\[x=\frac{200}{43}\]

Answer 4

exactly! thanks thats how I got it

Answer 5

Good job mate.