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OpenStudy (anonymous):
how to solve this using absolute value... /X^2-3X-10/=5
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OpenStudy (anonymous):
|x^2 - 3x - 10| = 5 x^2 - 3x -10 = 5 and x^2 -3x-10 = -5
OpenStudy (anonymous):
x^2 - 3x -15 = 0 and x^2 -3x -5 = 0 now can you find x in both the cases
OpenStudy (anonymous):
|dw:1359986329843:dw|
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