Question

simplify the sum of (w^2+2w-24)/(w^2+w-30)+8/(w-5)

Answer 1

\[\frac{w^2+2w-24}{(w-5)(w+6)}+\frac{8}{w-5}\]
\[=\frac{w^2+2w-24+8(w+6)}{(w-5)(w+6)}\] then algebra in the numerator
distribute and combine like terms