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use the quadratic formula to find any x-intercepts on the graph of the equation. y=x^2 - 8x -1 x=?
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set y =0, and solve the quadratic equation
\[x ^{2}-8x-1=0\]
Set a=1, b=-8 and c=-1 in the QF.
\[x=4+\sqrt{17} or x=4-\sqrt{17}\]
yup exactly
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you need to use the quadratic formula
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
so the final answer would be
\[(4+\sqrt{17}, 0) and (4-\sqrt{17}, 0)\]
8 square root 68 over 8?
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yup
is it over 4?
if a =1 yes
so am i right? it is over 4
over 2x1
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