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solve cubed root of 2 times the square root of 3 times the 4th root of two
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\[\sqrt[3]{2}*\sqrt{3}*\sqrt[4]{2}\]?
yes @whpalmer4
There isn't anything to solve there, are we supposed to simplify it?
yeah, sorry thats what i meant
Rewrite it in exponential form: \[\sqrt[n]{x} = x^{1/n}\] Then recall that \[a^n*a^m = a^{n+m}\]
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okay i wrote them in exponential form but i dont get it after that
What do you have for your exponential form?
2^(1/3) * 3^(1/2) * 2^(1/4)....is that right?
\[2^{1/3}*3^{1/2}*2^{1/4}\]I see two parts of that with a common base, remember that \[a^n*a^m = a^{n+m}\]
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