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OpenStudy (anonymous):
Evaluate the integral of tan 3x dx
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OpenStudy (blurbendy):
use substitution. let u = 3x du=3dx dx = 1/3du 1/3 (integral sign) tan(u)du = - 1/3ln|cos(u)| + C = -1/3ln|cos(3x)|
OpenStudy (blurbendy):
+ C
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