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Mathematics 8 Online
OpenStudy (anonymous):

Is my work correct?

OpenStudy (anonymous):

\[4^{-2x}*4^{x}= 64 \]

OpenStudy (anonymous):

x = -3

OpenStudy (anonymous):

\[2^{x}*\frac{ 1 }{ 32 }=32\]

OpenStudy (anonymous):

x=10

OpenStudy (anonymous):

\[64 * 16^{-3x}=16^{3x-2}\] This on I'm confused on. x=0?

OpenStudy (anonymous):

Correct for both.

OpenStudy (anonymous):

Last one I will show you.

OpenStudy (anonymous):

\[4^3\times (4^2)^{-3x}=(4^2)^{3x-2}\] \[4^3\times 4^{(2)(-3x)}=4^{2(3x-2)}\]

OpenStudy (anonymous):

\[4^{3-6x}=4^{6x-4}\] \[3-6x=6x-4\] \[12x=7\]

OpenStudy (anonymous):

Oh, I see what I did! I cancelled out -6x with the positive 6x. lol, thank you very much!

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