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\[4^{-2x}*4^{x}= 64 \]
x = -3
\[2^{x}*\frac{ 1 }{ 32 }=32\]
x=10
\[64 * 16^{-3x}=16^{3x-2}\] This on I'm confused on. x=0?
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Correct for both.
Last one I will show you.
\[4^3\times (4^2)^{-3x}=(4^2)^{3x-2}\] \[4^3\times 4^{(2)(-3x)}=4^{2(3x-2)}\]
\[4^{3-6x}=4^{6x-4}\] \[3-6x=6x-4\] \[12x=7\]
Oh, I see what I did! I cancelled out -6x with the positive 6x. lol, thank you very much!
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