Question

Find the real x-values: (x)^3 - 3x-1 = 0

Answer 1

Sum and product of roots of a cubic I think.
\[ax^3 + bx^2 + cx + d=0\]
\[p+q+r=\frac{-b}{a}\]
\[p+q+r=0\]
\[pqr=\frac{-d}{a}\]
\[pqr=\frac{1}{1}\]

Answer 2

p, q and r are the x-values.
\[pq+pr+qr = \frac{c}{a}\]
\[pq+pr+qr = -3\]

Answer 3

I think you need to use trial and error instead.

Answer 4

Refer to the Mathematica attachment.