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how do I turn (4x-1) into (1-4x)
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\[-(4x-1) =-(4x)-(-1)=-4x+1=1-4x\] So basically (4x-1) = -(1-4x) and (1-4x) = -(4x-1)
So multiply by -1
Yes.
(4x-1) * -1 = -(4x-1) = -4x + 1 = 1 - 4x
Do I have to multiply a numerator too
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I have 24x^4-8x^3+3/(4x-1)^2 And on wolfram it simplifies to 24x^4-8x^3+3/(1-4x)^2
Depends on the problem. But if you multiply a numerator by -1, you must distribute a -1 to the denominator as well. Example: \[\frac{(4x-1)}{1-4x}=\frac{-(1-4x)}{1-4x} = -1\]
\[ (4x-1)^2 = (4x-1)(4x-1)=-1(1-4x)*-1(1-4x)\] \[=(-1)^2(1-4x)^2=(1-4x)^2\]
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