Question

Graph the function in the interval from 0 to 2pi.

Answer 1

If this is y=sin(x) from 0 to 2pi, what would y=sin(x-2) from 0 to 2pi look like?

Answer 2

like this?

Answer 3

Close. When f(x)=sinx, f(0)=sin(0)=0. If f(x)=sin(x-2), f(2)=sin(2-2)=sin(0)=0. So your new function "starts" at x=2, so shift the whole graph to the right.