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Mathematics 12 Online
OpenStudy (anonymous):

how to differentiate y=sin(lnx)? help please..

OpenStudy (amoodarya):

|dw:1360065673873:dw| chain rule

OpenStudy (stamp):

\[u=lnx\]\[du=x^{-1}dx\]\[dy/dx=cos(u)du\]\[dy/dx=\frac{cos(lnx)}{x}\]

OpenStudy (anonymous):

oh? got it ! thanks :))

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