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OpenStudy (anonymous):
how to differentiate y=sin(lnx)? help please..
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OpenStudy (amoodarya):
|dw:1360065673873:dw| chain rule
OpenStudy (stamp):
\[u=lnx\]\[du=x^{-1}dx\]\[dy/dx=cos(u)du\]\[dy/dx=\frac{cos(lnx)}{x}\]
OpenStudy (anonymous):
oh? got it ! thanks :))
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