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solve quadratic equations y=2x-16 y=2^2-3x-12
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I would use either the quadratic formula, or set the equations equal to zero and factor to find the solution.
Is this a system of equations?
yes
okay, so in the first equation y is solved for. So take that expression (2x-16) and plug it into the second equation where y is Also, is it supposed to be 2x^2 in the second equation?
y=x^2-3x-12
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Alright, so put 2x-16 where y is 2x-16=x^2-3x-12 can you try to solve for x now?
Thanks
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