Question

A rectangle's width is one-seventh it's length, it's perimeter is 80 m. Find the dimensions of the rectangle. The length is and the width is?

Answer 1

So, we know that:

W = (1/7)L
And we know that P = Perimeter = 80 m = 2L + 2W

So, we sub and get:

80 = 2L + 2((1/7)L)
80 = 2L + (2/7)L
80 = (16/7) L
Solve for L to get: L = 35 m

Then put 35 m in original equation: so:

W = (1/7)L = (1/7)*35 = 5

Therefore length = 35m and w = 5 m.