Physics Question please help?

2. A block of mass 5kg sits on an inclined plane, which is slowly being raised. The block remains motionless until the angle the plane makes with the horizontal is 22°. At this angle, the block begins to slide down the plane. What is the coefficient of static friction between the plane and the block?

I got it to this
cos 22(50) = Fwy
sin 22(50) = Fwx (Fw is weight)

and then...

F_net = ma
friction - Fwx = ma
but this doesnt seem right considering

Question

Physics Question please help?

2. A block of mass 5kg sits on an inclined plane, which is slowly being raised. The block remains motionless until the angle the plane makes with the horizontal is 22°. At this angle, the block begins to slide down the plane. What is the coefficient of static friction between the plane and the block?

I got it to this 
cos 22(50) = Fwy
sin 22(50) = Fwx (Fw is weight)

and then...

F_net = ma
friction - Fwx = ma
but this doesnt seem right considering

shane_b · Answer

$$\Large u_k=tan(\theta)$$For a decent explanation as to how this was derived go here: http://www.understandingforce.com/coefficientofstaticfriction.html

anonymous · Answer

I dont understand how this would come about? in this instance?

shane_b · Answer

I can't explain it any better than the site I posted

anonymous · Answer

can you tell me what you got as the answer? some how i ended up with 1.54?