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Mathematics 23 Online
OpenStudy (anonymous):

Help with this problem? I'll post the picture.

OpenStudy (anonymous):

To solve for x, first cross multiply. Isolate the variable and you're good to go.

OpenStudy (anonymous):

like: 5(x+1)= 3(x+2)

OpenStudy (anonymous):

Use the distributive poperty next.

OpenStudy (anonymous):

u distribute 5 and 3 \[5x+5=3x+6\] then you group the terms with x\[5x-3x=6-5\] \[2x=1\] \[x=1\div2\]

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