Question

can someone solve this? heping my friend on her homework. best answer gets medal
5x^-3y^2/x^5y^-1 * (2xy^3)^-2/xy

Answer 1

do you mean \[(5x^{3}-3y^{2}/x^{5}y^{-1})\times((2xy^{3})^{2}/xy) or (5x^{3}-3y^{2}/x^{5}y^{-1}\times(2xy^{3})^{2}/xy)\]

Answer 2

\[5x ^{-3}y ^{2}/x ^{5}y ^{-1}\times(2xy ^{3})^{-2}/xy\]

Answer 3

@DarthTony

Answer 4

\[\large \frac{ 5x^{-3}y^{2}}{ x^5y^{-1} }\times \frac{ (2xy^3)^{-2} }{ xy }=5x^{(-3)-(5)}y^{(2)-(-1)}\times \frac{ 2x^{-2}y^{3(-2)} }{ xy }\]
\[\large =5x^{-8}y^{2+1}\times \frac{2x^{-2}y^{-6}}{xy}\]
\[\large =5x^{-8}y^3 \times 2x^{(-2)-(1)}y^{(-6)-(1)}\]
\[\large =5x^{-8}y^3 \times 2x^{-3}y^{-7}\]
\[\large =(5\times 2)x^{(-8)+(-3)}\times y^{(3)+(-7)}\]

Answer 5

\[\large =10x^{-11}\times y^{3-7}\]
\[\large =10x^{-11}\times y^{-4}\]
\[\large =10x^{-11}y^{-4}\]