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please show me how to factor completely 3y^2-42y-96
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factor a 3 out 3(y^2-14y-32) try solving it. if you have trouble just ask and I can help you with the next step.
im so confused i dont even know where to start i know the common is 4
ok i was so wrong common is not 4
3(y-16)(y+2) -16+2 = 14 -16*2 = -32
write the middle term as the sum of 2 terms in such a way that you will have a common factor.
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im gonna try another one and see if i can get it
that's a good idea.
10-19s+6s would this one be considered prime there are no numbers that go into 19?
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