factor completely -2x^2+3x+9 HELP
ok, can you find 2 numbers whose sum is +3 and product is -2*9=-18 ?
i cant im confused
what are the factors of 18 ?
12369
yes, so which 2 numbers among then will give you difference of 3 ?
1and2
that will give sum=18 since you have -18, you'll need difference =3
*that will give sum=3
oh ok so 6-3
yes! so, you write middle term as 3x =6x-3x
-2x^2+3x+9 = -2x^2+6x-3x+9 can you solve further ?
just factor -2x from first 2 terms and -3 from other 2.
so i would get x^2+6x-3 right
-2x^2+3x+9 = -2x^2+6x-3x+9 =-2x(....- ....) -3 (...-...) can you fill out the blanks ?
x-3 x-3
yes,-2x^2+3x+9 = -2x^2+6x-3x+9 =-2x(x-3) -3 (x-3) now last step, factor (x-3) from above, what u get ?
im a lil confused not sure
-2x^2+3x+9 = -2x^2+6x-3x+9 =-2x(x-3) -3 (x-3) =(-2x-3)(x-3) its just like ab+cb = (a+c)b
ok thank you i understand how you get it when i see it complete i just not sure of the operations :)
welcome ^_^
hope you can help me with future probs ill probably be here all night
i hope so, too :) but if i am unavailable, there r many to help you :)
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