Help finding the complex zeros of a function! F(x)=x^4+2x^3+46x^2+98x-147
147=3*7*7 --------------- 147=21(7) 147=3(49) Try using synthetic division with the following values x=+ or - {1,3,7,21,49,147}
Ok, so does it matter what I chose to divide by?
It doesn't matter where you start but if you don't get the remainder zero you can throw the number you tried out.
Perfect!!! Thanks for your assistance you rock!!!
Np. I like to at least try to guess ones that are more possible than others and try those because that is a lot to try. lol
Ok, I did them all, and found there were no complex zeros do you think that's correct!
Nope. :(
Oh man, I was looking at the wrong numbers, I'm redoing my math now :-) one second and ill send what I found :-)
Okay, -3, and 1 :-)
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