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Factor the difference of two squares, repeat the procedure as often as necessary (be sure to give all the final factors in your answer). Check by FOIL. Enter the sum of two squares first. n4 - 1
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\[(n^2+1)(n^2-1) \] the general form of the difference of squares is \[(a^2 - b^2) = (a+b)(a-b)\]
the 2nd binomial factor is still the difference of 2 squares |dw:1360179198189:dw| so there will be 2 binomial factors in the answer...
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