Please help me! :(
ok what is yoour problem
it is down below
@precal @Luis_Rivera @ghazi @amistre64 can you guys help me ?
@jazy can you able to help me with this?
@perl
@aaronq @AccessDenied @JamesJ @saifoo.khan
I need help badly @JamesJ :(
Well, I recommend you plot these points on a graph so you can see the relationship very clearly. That will help you a lot.
8 is a y and 6 is x, so?
You are told what are the x values and what are the y values. Draw the graph. This will help you see what's going on. That is the most instructive piece of help I can give you right now. I'm not going to give you the answer.
I am not looking for answer, i just dont understand how to do it, cuz i tried once and failed
@ksaimouli help me to solve it please
@jazy thank you for coming!
please help me to solve, i did once n i failed to do it correctly
Thank you for coming @ksaimouli!
@Faman39 it is 6+8x initial=6 where as x represents number of minutes,
u can check if u want to
let pick x=0 (6+0)=6 so our equation is right
but what about total cost ?
Do not give answers! Normally I would delete this but I am going to leave it here and ask you to explain carefully how you arrived at your answer.
i meant call cost
how will i find it exactly
@Faman39 i gave the most of it it's time to figure it out by urself think think
@ksaimouli @JamesJ i just came to understand what was my mistake, so i dont make again in the future, i just didnt understand
you guys can see what i wrote
@ksaimouli, walk him through your process. Pottery Barn rule: you break it, you pay for it. Here it is this: You answer it, you explain it.
okay first they gave the initial value right no matter what that is constant so what is initial value in this problem @Faman39
6 cent
yup so 6 + in addition to that they provided --- cents for 1 min
we dont know what --- so i said x
let the ---- be x
so 6+8x
Do i have to make x 8?
total cost is nothing but adding those i think
they gave u the cost for certain min
I m just confuse how to find total cost in it
should i add this 6+ 8?
or have to do something differently
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