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Solve: (4x - 5)(3x + 2) =0 {5, -2} {5/4, - 2/3} {-5/4, 2/3} no solution
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Well, set both (4x-5) = 0 and (3x+2) = 0 and solve each case, what do you get for x? (BTW, it's not the last option ;D)
ok one sec
ok got it thansk!!
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