The perimeter of a rectangle is 68 feet. The length of the rectangle is 4 feet more than twice the width. Find the length and the width of the rectangle. Explain your reasoning.

Question

The perimeter of a rectangle is 68 feet.  The length of the rectangle is 4 feet more than twice the width.  Find the length and the width of the rectangle.  Explain your reasoning.

anonymous · Answer

Perimeter = 68
or
P = 68

P = 2L + 2W (twice the length plus twice the width)

P = 2(4+2W) + 2W
P = 8 + 6W
60 = 6W
10 = W

then

68 = 2L + 2W
68 = 2L + 20
24 = L

width = 10 length = 24