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Pre-Algebra
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Not understanding how to work sum of cubes 125x^3+27y^3
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do u need to factor them
then use a^3+b^3= (a+b)(a^2 -ab+b^2)
for a^3-b^3= (a-b)(a^2 +ab+b^2)
\[ 125x^3+27y^3 = (5x)^3 + (3y)^3\]
if u need not factor them then use a^3+b^3 =(a+b)^3 -3ab(a+b)
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Now a = 5x and b =3y.
125x^3+27y^3 =(5x)^3 +(3y)^3 =(5x+3y)(25x^2 -15xy +9y^2)
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