Please help, find area! stuck.
use triangle with 5|dw:1360263133804:dw|note that both skew lines are 13 get the height
i cant believe i forgot how to find the area XD lets see if i can remember
I know its base times height. SO wouldn't it be 22 + 5 which is 27 times 13?
I have nooo clue, i learned that so long ago and forgot all about it
@Jonask im confused?
sry i mean we dont know height get height 13^2=5^2+h^2
look at the diagonal its the same on both sides|dw:1360263753146:dw|
still don't get it. Wouldn't you just add 22 + 5 and then times it by 13?
area of parrallelo gram A=ab it has nothing to do with the 5 so the height can be viewed as insidedont add it|dw:1360263898477:dw|
so 13 times 22?
I ment 22 times 5?
well 22 is not a heght it is a (diagonal)slant height hence we have to calculate the real height |dw:1360264160546:dw|
oh okay so 65?
but I thought 5 was the height?
13^2=5^2+h^2 h^2=144 h=12 A=ab
Its still confusing. lol but thank you!
so it would be 65, since its 5 the base times 13 the height?
Can you help me on another qt? @Jonask
previuos question not correct we got height=12 base=22 A=12(22)=264
2 3rd option
are you sure for the area?
yes
thanks!
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