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A charged particle is projected in the air such that its horizontal (x) and vertical (y) shifts are given by x(t) = 10t − t2 and y(t) = 6t, where x and y are in meters and time t is in seconds. What is the ratio of y to x at t = 4 seconds?
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\[y(t):x(t) = \frac{6t}{10t-t^2}\]Evaluate that at \(t = 4\)
A. 0.25 B. 2 C. 0.75 D. 0.85 E. 1
Yeah, it's one of those. Do the arithmetic.
dont have a calculator
Don't need one. What's 6*4?
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What's 10*4 What's 4*4 What's \[\frac{6*4}{(10*4)-(4*4)}\]
24
No. \[\frac{6*4}{(10*4)-(4*4)}= \frac{24}{40-16} = \frac{24}{24} =? \]
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