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Find the sum: (3x2 + 5x + 8) + (6x2 + 3x + 2)
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PLEASE HELP
Collect like terms. add up the x^2 terms, add up the x terms, add up the numeric terms. For example \[(x^2 + 2x + 1) + (3x^2 + 4x + 2) = (1+3)x^2 + (2+4)x + (1+2) = 4x^2 + 6x + 3\]
Then what ?
Then you're done! What do you get?
3X²+2X+6 ?
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What is 3x^2 + 6x^2? What is 5x + 3x? What is 8 + 2? What do you get when you add those three answers together?
\[(aX^{2}+bX+c)+(qX^{2}+rX+s)=(a+q)X^{2}+(b+r)X+(c+s)\]
(3x2 + 5x + 8) + (6x2 + 3x + 2) 3x^2+ 6x^2= 9x^2 5x+3x=8x 8+2=10 So you get 9x^2 +8x +10
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