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Mathematics 8 Online
OpenStudy (anonymous):

Log 100x=1/2

OpenStudy (anonymous):

Well.. if u put e on the both side, u will get: e^(log 100x)=e^(1/2) => 100x=e^(1/2) 0> x=e^(1/2)/100

OpenStudy (anonymous):

This time the e is an exponent :D

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