Could someone please help me with this..?
Jerry inscribed a quadrilateral ABCD in a circle, as shown below.
If the measure of arc BCD is 250°, what is the measure of angle BCD?
70˚
75˚
55°
80°
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OpenStudy (anonymous):
OpenStudy (ryan123345):
55 :)
OpenStudy (anonymous):
@ryan123345 do u mind explaining how..?
OpenStudy (ryan123345):
sure :)
OpenStudy (anonymous):
thank u!!!! a million times!!
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OpenStudy (anonymous):
cuz im completely lost..
OpenStudy (ryan123345):
your welcome :) lol
OpenStudy (ryan123345):
ok so it tells you that arc BCD is 250.
OpenStudy (ryan123345):
since its and inscribed quadrilateral that means the angle opposite from BCD which is BAD is half. So from there u know that BAD is half of 250 so u know BAD is 75
OpenStudy (ryan123345):
no sorry not 75 lol
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OpenStudy (anonymous):
55?
OpenStudy (ryan123345):
half of 250 is 125. so than u know that BAD is 125
OpenStudy (anonymous):
whoops..
OpenStudy (ryan123345):
than when u get that u know that in an inscribed quadrilaral opposite angles are supplimentary (add up to 180) so to find BCD u get 125 and subtract if from 180 to get 55 :)
OpenStudy (anonymous):
wow. thank u sooo much are u in geometry too?
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