Question

BDFH is a rectangle with a width of 5 and a length of 12. One diagonal is 2x + 3y and the other diagonal is x + 8y. Find the values of x and y.

x = 4 and y = 1

x = 4 and y = -1

x = 5 and y = 1

x = 5 and y = -1

Answer 1

@RadEn

Answer 2

@uri

Answer 3

hint : diagonal = sqrt(l^2 + w^2)
l=length, w=width

Answer 4

so wt do i do 5^2 + 12^3?

Answer 5

5^2 = 5 * 5 = 25 and 12^2 = 12 * 12 = 144
add of them, and take squareroot after that

Answer 6

so add 144 + 25
= 169

Answer 7

sqrt(169) = ... ?

Answer 8

13

Answer 9

bt thats not an answer option

Answer 10

so wt do i do now

Answer 11

yes, it just a start

Answer 12

now, the diagonal represnted by equations : d=2x + 3y and d=x+8y
and we knowed that the length of diagonals of rectangle is same, so
2x+3y=13 and
x+8y=13
solve for x and y by elimination or subt method

Answer 13

or u can do trial error from ur options

Answer 14

i got it
x= 5 y = 1

Answer 15

yep, that's correct

Answer 16

thank you

Answer 17

you're welcome