Question

How would I solve 125^(-1/3)?

Answer 1

You can use the following"
\[n ^{-\frac{1}{a}}=\frac{1}{n ^{\frac{1}{a}}}=\frac{1}{\sqrt[a]{n}}\]

Answer 2

125^(1/3) = (5^3)^(1/3) .............. 125 = 5^3

= 5 ........... (3 and 1/3 will cancel out)
Hope this helps @DanielAcedo