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Hi, I need some help with a natural log problem: Determine the value of x if 6.03(1.23)^x=32.403. I have absolutely no clue how to re-format this. What would the first step be?
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6.03(1.23)^x = 32.403 first divide the 6.03 1.23^x = 5.374 change this to a log log1.235.374=x Now just use the change of base formula to solve it. (log 5.374)/(log 1.23) = x
Awesome, thanks!
no prob. glad to help
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