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f(x) = 1/3x − 2 and g(x) = −2x − 1, find (f • g)(9)
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f(g(9))=f(-2(9)-1)=f(-18-1)=f(-19).... put x=-19 in f(x)
Find g(9) and plug it in for f(x)\[f(g(9))=\frac{1}{3}g(9)-2\]
-19?
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