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Mathematics 21 Online
OpenStudy (anonymous):

The perimeter of a rectangle is 50 cm and the length is 4 cm longer than the width. Write and solve the system of equations using the substitution method. A. width = 10 cm, length= 14 cm B. width = 10 1/2 cm, length= 14 1/2 cm C. width = 11 cm, length= 15 cm D. width = 23 cm, length= 27 cm

OpenStudy (anonymous):

There are four sides, so to find the perimeter we just add them all up perimeter=length+length+width+width

OpenStudy (anonymous):

we can simplify this expression by using multiplication because width+width=2×width and length+length=2×length so the perimeter equation looks like this perimeter=2×length+2×width this problem gives us two pieces of information that we can insert into out equation for perimeter The perimeter = 50 and that the length is 4 more than the width so we can write the length like this length=width+4 we can substitute both of these pieces of information into the equation for perimeter perimeter=2×length+2×width

OpenStudy (anonymous):

to get: 50=2×(width+4)+2×width By substituting length with width + 4 we reduced the equation to a single variabale which we can solve.

OpenStudy (anonymous):

can u handle it from here

OpenStudy (anonymous):

i dont even get it or anything you just said

OpenStudy (stamp):

@brittanyburton Use the "Draw" button to illustrate for us the situation at hand. Label as much information that has been given to you as you possibly can.

OpenStudy (anonymous):

thats all the info...lol word 4 word

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