The perimeter of a rectangle is 50 cm and the length is 4 cm longer than the width. Write and solve the system of equations using the substitution method. A. width = 10 cm, length= 14 cm B. width = 10 1/2 cm, length= 14 1/2 cm C. width = 11 cm, length= 15 cm D. width = 23 cm, length= 27 cm
There are four sides, so to find the perimeter we just add them all up perimeter=length+length+width+width
we can simplify this expression by using multiplication because width+width=2×width and length+length=2×length so the perimeter equation looks like this perimeter=2×length+2×width this problem gives us two pieces of information that we can insert into out equation for perimeter The perimeter = 50 and that the length is 4 more than the width so we can write the length like this length=width+4 we can substitute both of these pieces of information into the equation for perimeter perimeter=2×length+2×width
to get: 50=2×(width+4)+2×width By substituting length with width + 4 we reduced the equation to a single variabale which we can solve.
can u handle it from here
i dont even get it or anything you just said
@brittanyburton Use the "Draw" button to illustrate for us the situation at hand. Label as much information that has been given to you as you possibly can.
thats all the info...lol word 4 word
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