The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method.
A. -2 and -4
B. -2 and 4
C. 2 and -4
D. 2 and 4

Question

The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method.
	A.	-2 and -4
	B.	-2 and 4
	C.	2 and -4
	D.	2 and 4

anonymous · Answer

Let x = first number
y = second number

You're given
$$\begin{cases}5x+2y=8\
3x-7y=-22\end{cases}$$
Do you know how to solve that?

anonymous · Answer

siths is 100% right

anonymous · Answer

yes solve it by making any one of the variable common in both the equations

anonymous · Answer

like multiply first eqn wid 7 and secnd eqn wid 2

anonymous · Answer

(5x+2y) x 7 = 8 x 7
35x + 14y = 56