Given the triangle below, what is cot∡B?
Right triangle ABC with AC measuring 4 and BC measuring 7
square root of 33 over 4
7 times square root of 33 over 33
square root of 33 over 7
4 times square root of 33 over 33
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OpenStudy (anonymous):
this one?
OpenStudy (anonymous):
yess Imma Post the Picture (:
OpenStudy (anonymous):
k
OpenStudy (anonymous):
OpenStudy (anonymous):
No /:
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OpenStudy (anonymous):
do you know how to use the pythagorean theorem to find the missing side of the triangle?
OpenStudy (anonymous):
Lol Nope But my older brother thinks its square root of 33 over 7 is he right ?
OpenStudy (anonymous):
no.... it's not \(\large \frac{\sqrt{33}}{7} \)
do you know where the \(\large \sqrt{33} \) came from though?
OpenStudy (anonymous):
Sadly No /.\
OpenStudy (anonymous):
Nvm My Sister Explained It Thanks Though (:
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OpenStudy (anonymous):
ok... the sqrt(33) came from the pythagorean theorem: \(\large a^2+4^2=7^2 \)
solving that you'll get \(\large a=\sqrt{33} \)
but now the trigonometry part...
cotangent is adjacent over opposite...
ok.... nvmd..