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A 2,493-kg car is moving down a road with a slope (grade) of 14% at a constant speed of 13 m/s. What is the direction and magnitude of the frictional force? (define positive in the forward direction, i.e., down the slope)?
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I know how to convert the percentage to degrees already
how did u convert?
using the inverse of tangent
i hate conversions -_-
I know lol
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You can immediately discern the direction of the friction as friction is defined to be against the motion in most cases. From there you can set up a drawing somewhat like this|dw:1360371064108:dw|
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