Question

height (in feet) of a ball thrown horizontally

y=-(1/14)x^2) +2x +6

how high is it when it leaves the ground?
Maximum height of the ball?
how far does it go?

Answer 1

What is x? The horizontal distance?

Answer 2

yes

Answer 3

Well, the height when thrown is the value of y when x = 0.

The function gives you an inverted parabola. Find the vertex and you know the maximum height.

Find the value where y = 0 and x > 0 and you know how far it goes.