height (in feet) of a ball thrown horizontally

y=-(1/14)x^2) +2x +6

how high is it when it leaves the ground?
Maximum height of the ball?
how far does it go?

Question

height  (in feet) of a ball thrown horizontally

y=-(1/14)x^2) +2x +6

how high is it when it leaves the ground? 
Maximum height of the ball?
how far does it go?

anonymous · Answer

What is x?  The horizontal distance?

anonymous · Answer

yes

whpalmer4 · Answer

Well, the height when thrown is the value of y when x = 0.

The function gives you an inverted parabola.  Find the vertex and you know the maximum height.

Find the value where y = 0 and x > 0 and you know how far it goes.