Question

f(x)=3x^2+4x+1
f(x)=3(x+a)^2+b
solve a and b

Answer 1

i have got
a=2/3
b=-1/3
Is this right ?

Answer 2

are they both f(x)?

Answer 3

yeah
3(x+a)^2+b=3x^2+4x+1

Answer 4

expand 3(x+a)^2 and 3x^2 first

Answer 5

I guess I want to see how you came up with your answers.

Answer 6

3x^2+6xa+3a^2+b=3x^2+4+1
6a=4 ............ a=2/3
3a^2+b=1 .....b=-1/3

Answer 7

2/3 and -1/3 it is

Answer 8

both function are same .so we can write as bellow
3(x+a)^2=3x^2+6xa+3a^2
so 6xa=4x
a=2/3
and 3a^2+b=1
3*(2/3)^2+b=1
b=-1/3