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Applied Multimedia 9 Online
OpenStudy (jaweria):

Can anyone help me here with java problem?

OpenStudy (konradzuse):

hi, yes.

OpenStudy (jaweria):

oh really Can you please

OpenStudy (konradzuse):

you should post your question if you want help.......

OpenStudy (jaweria):

Yes I have two questions. First question is this: Write a for loop that prints in ascending order all the positive integers less than 200 that are divisible by both 2 and 3, separated by spaces. The answer that I got for this question is this: int i; for (i=0;i<200; i++) { if(i%2==0 i%3==0) { System.out.println [i]; } } But it says that something is wrong can you please check it for me? My second question is this: 1.05: Range Write in a Java program to read two integers and display the number of integers that lie between them, including the integers themselves. For example, there are four integers are between 3 and 6: 3, 4, 5, and 6. Input Notes: The input consists of two integers typed at the console. Output Notes (Prompts and Labels): The program's first line of output is: My answer that I got is this: Range import java.util.Scanner; class { public static void main(String args[]) { int n1,n2; Scanner in = new Scanner(System.in); System.out.println('a'); n1 = in.nextInt(); System.out.println('b'); n2 = in.nextInt(); for(int i=n1;i<n2;i++) //print i } } But Its telling me that its wrong.

OpenStudy (konradzuse):

if(i%2==0 i%3==0) { System.out.println [i]; } if(i%2==0 || i%3==0) { System.out.println [i]; }

OpenStudy (konradzuse):

What are your errors for the second one? All I see is that it should be <=n2?

OpenStudy (jaweria):

But I dont get it what is my error for the first one?

OpenStudy (jaweria):

what I need to fix in there?

OpenStudy (konradzuse):

if(i%2==0 i%3==0) if(i%2==0 || i%3==0)

OpenStudy (konradzuse):

|| = or && = and

OpenStudy (jaweria):

how am I going to get that two parallel lines

OpenStudy (konradzuse):

shift + \ <- above enter

OpenStudy (jaweria):

Now its giving me an error of this [i]

OpenStudy (konradzuse):

System.out.println [i]; System.out.println([i]);

OpenStudy (konradzuse):

going to bed now.

OpenStudy (jaweria):

ok thanks though

OpenStudy (rsmith6559):

Square brackets are used syntactically for indexes into arrays, maps, etc. They have to be used with the name of the structure: foo[ i ] System.out.println is a method of the System object. Function notation uses parentheses, so it would be: System.out.println( i );

OpenStudy (jaweria):

i tried this but still giving me an error.

OpenStudy (rsmith6559):

What is the error?

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