Question

Evaluate indefinite integral of ∫[v+(1/(3v-1)^3)]dv.

Answer 1

∫[v+(1/(3v-1)^3)]dv = ∫v dv + ∫[1/(3v-1)^3]dv
∫v dv = ... ( it's easy :)
∫[1/(3v-1)^3]dv
use integral by u-sub
u = 3v - 1
du = 3 dv or dv = du/3
continue it ...