Question

sec x / (1 + sec x) = (1- cos x) / sin ^2 x

Answer 1

\[\huge \frac{\sec x}{1+\sec x}=\frac{\frac{1}{\cos x}}{1+\frac{1}{cosx }}\]

Answer 2

\[\huge \frac{1}{(\cos x)\left( 1+\frac{1}{\cos x} \right)}\]

Answer 3

:)

Answer 4

\[\huge =\frac{1}{1+ \cos \ x}\]

Answer 5

\[\huge =\frac{1}{1 + \cos \ x}\times\frac{1-\cos \ x}{1- \cos \ x}\]

Answer 6

Maybe you can do it from here? :>

Answer 7

thank you :)

Answer 8

:)