Question

Graph the function. Identify the vertex and axis of symmetry.
f(x)=-2x^2+2x-1

Answer 1

\[ax^2+bx+c=0\]
\[f(x)=-2x^2+2x-1\]
Axis of symmetry and vertex's x-value
\[x=-b/2a\]
\[x=-2/(2*-2)=1/2\]
Vertex's y-value
\[y=c-b^2/4a\]
\[y=-1-2^2/(4*-2)\]
\[y=-1/2\]
Vertex Coordinates\[(1/2,-1/2)\]

Answer 2

is this the graph

Answer 3

axis of symmetry:
vertex: (–0.5, –0.5)

Answer 4

You originally mentioned the function \[f(x)=-2x^2+2x-1\]
The image is not the graph.

Answer 5

i have graphs as an answer
u said 1/2 so its -0.5 right?