Question

i need help with a Quadratic formula please

Answer 1

\[x=\frac{ -1+\sqrt{-47} }{ 8 }\]
this what i have so far now what do i do

Answer 2

when i tried to sq. root it was a long decimal #

Answer 3

Could you post the original function, this will result in an imaginary root.

Answer 4

\[4x ^{2}-x-3=0\]

Answer 5

this is what i started with

Answer 6

i figured this one out i did it wrong the first time

Answer 7

\[4x^2-x-3=0\]
\[x^2-\frac{1}{4}x-\frac{3}{4}=0\]
\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
\[x = \frac{-(-\frac{1}{4}) \pm \sqrt{(-\frac{1}{4})^2-4(1)(-\frac{3}{4})}}{2(1)}\]
\[x = \frac{\frac{1}{4} + \frac{7}{4}}{2}=1\]
\[x = \frac{\frac{1}{4} - \frac{7}{4}}{2}=-\frac{3}{4}\]