Question

Solving Trig Equations:
a.) 2 sin x - csc x = 0

Answer 1

How do you solve?

Answer 2

csc x =1/sinx ----> 2sin x -1/sinx =0
(2sin^2 x -1 )/sinx =0 iff 2sin^2 x -1 =0
---> 2sin^2x =1 --->
sin^2x =1/2--->
sin x = +- 1/4 ---> x = +- arcsin (1/4)

Answer 3

This is confusing. How did you get what you got?