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(square root of t-2) /(3t-9)
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\[\frac{\sqrt{t-2}}{3t-9}\]
yes need the domain of it.
@Zelda, the domain is limited to more than just that
Oops, sorry.
No es cualquier cosa,como parte de la función es racional "t es diferente de 3" ademas t-2>= 0 ; eso es el dominio. suerte!.
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Hint: Solve t - 2 > 0 and 3t - 9 ≠ 0
t=2 and t does not equal to 3
sorry, t ≥ 2 and t ≠ 3 or [2, 3) (3, ∞)
@Hero "t" si es Igual a 2, el Dom f = [2, ∞), t ≠ 3
I don't see any difference in what you wrote from what I wrote
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pusiste t ≠ 3 o 2
Mind saying that in English?
no entiendo
\(\sqrt{0} = 0\)
\(\sqrt{2 - 2} = 0\)
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que con eso
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